document.write( "Question 246045: The sum of Father and son’s age is 60 years. Six years ago the age of father is twice the son s age, then the current age of the father is \n" ); document.write( "

Algebra.Com's Answer #179796 by richwmiller(17219) $\"\"$ $\"About$

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let s= son's age and f= father's age
\n" ); document.write( "f+s=60
\n" ); document.write( "f=60-s\r
\n" ); document.write( "\n" ); document.write( "f-6=2(s-6)
\n" ); document.write( "substitute 60-s for f\r
\n" ); document.write( "\n" ); document.write( "60-s-6=2(s-6)
\n" ); document.write( "combine
\n" ); document.write( "54-s=2s-12
\n" ); document.write( "add 12
\n" ); document.write( "66-s=2s
\n" ); document.write( "add s
\n" ); document.write( "66=3s
\n" ); document.write( "divide by 3
\n" ); document.write( "22=s son is 22
\n" ); document.write( "f+22=60
\n" ); document.write( "subtract 22
\n" ); document.write( "f=38 father is 38
\n" ); document.write( "check\r
\n" ); document.write( "\n" ); document.write( "f-6=2(s-6)
\n" ); document.write( "38-6=2(22-6)
\n" ); document.write( "32=2*16
\n" ); document.write( "32=32
\n" ); document.write( "check\r
\n" ); document.write( "
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