document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246053>Question 246053</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the sequence 16, 80, 48, 64, A, B, each term beyond the second term is the arithmetic mean (average) of the previous two terms. What is the value of B? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179790 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179790\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16, 80, 48, 64, 56, 60<BR>\n" );
document.write( "(80+16)/2=96/2=48<BR>\n" );
document.write( "(80+48)/2=128/2=64<BR>\n" );
document.write( "(64+48)/2=112/2=56 ans. for A<BR>\n" );
document.write( "(64+56)/2=120/2=60 ans. for B </SPAN>\n" );
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