document.write( "Question 246102: The hypotenuse of a right triangle is 2 units longer than the longer leg which is 14 units longer than the shorter leg. Determine the lengths of the three sides. How do i begin solving this question? \n" ); document.write( "
Algebra.Com's Answer #179787 by oberobic(2304)\"\" \"About 
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The Pythagorean Theorem is fundamental to the solution: \"c%5E2+=+a%5E2+%2B+b%5E2\"
\n" ); document.write( ", where
\n" ); document.write( "c = hypotenuse
\n" ); document.write( "a = longer leg
\n" ); document.write( "b = other leg
\n" ); document.write( ".
\n" ); document.write( "The problem setup gives you 3 important relationships.
\n" ); document.write( "\"c+=+a+%2B+2\"
\n" ); document.write( "and
\n" ); document.write( "\"a+=+b+%2B+14\"
\n" ); document.write( ".
\n" ); document.write( "So,
\n" ); document.write( "\"c+=+b+%2B+14+%2B+2+=+b+%2B+16\"
\n" ); document.write( ".
\n" ); document.write( "Of course,
\n" ); document.write( "\"b+=+b\"
\n" ); document.write( ".
\n" ); document.write( "Going back to the Pythagorean Theorem:
\n" ); document.write( "\"c%5E2+=+a%5E2+%2B+b%5E2\"
\n" ); document.write( ".
\n" ); document.write( "By substitution, we can cast the entire problem in terms of b, the shorter leg.
\n" ); document.write( "\"%28b%2B16%29%5E2+=+%28b%2B14%29%5E2+%2B+b%5E2\"
\n" ); document.write( ".
\n" ); document.write( "\"b%5E2+%2B+32b++%2B+256+=+b%5E2+%2B+28b+%2B+196+%2B+b%5E2+=+2b%5E2+%2B+28b+%2B+196\"
\n" ); document.write( ".
\n" ); document.write( "Subtract b^2 from both sides
\n" ); document.write( "\"32b+%2B+256+=+b%5E2+%2B+28b+%2B+196\"
\n" ); document.write( ".
\n" ); document.write( "Subtract 32b from both sides
\n" ); document.write( "\"256+=+b%5E2+-+4b+%2B+196\"
\n" ); document.write( ".
\n" ); document.write( "Subtract 256 from both sides
\n" ); document.write( "\"0+=+b%5E2+-+4b+-+60\"
\n" ); document.write( "so,
\n" ); document.write( "\"b%5E2+-+4b+-+60+=+0\"
\n" ); document.write( ".
\n" ); document.write( "Can we factor 60 such that the factors are 4 apart? 2*30? no 3*20? no. 4*15? no. 5*12? no. 6*10? yes!
\n" ); document.write( "\"%28b+-+10%29%28b+%2B+6%29+=+0\"
\n" ); document.write( ".
\n" ); document.write( "Thus we have two candidate values for b: 10 and -6. Since the leg of a triangle cannot be negative, the proposed solution is b = 10.
\n" ); document.write( ".
\n" ); document.write( "Substituting back into what we were told in the problem setup:
\n" ); document.write( "\"a+=+b+%2B+14+=+24\"
\n" ); document.write( "\"c+=+a+%2B+2+=+26\"
\n" ); document.write( ".
\n" ); document.write( "We always check our proposed solution. Here we just use the Pythagorean Theorem again.
\n" ); document.write( "\"a%5E2+=+24%2A24+=+576\"
\n" ); document.write( "\"b%5E+2+=+10%2A10+=+100\"
\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+676\"
\n" ); document.write( "\"c%5E2+=+26%2A26+=+676\"
\n" ); document.write( "That checks, so we have the correct answer.
\n" ); document.write( "Done.
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