document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246153>Question 246153</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If someone can help me understand on the steps of how to solve this word problem.\r<BR>\n" );
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document.write( "Different weights. Professor Williamson counts his midterm as 2/3 of the grade and his final as 1/3 of the grade. Wendy scored only 48 on the midterm. What range of scores on the final exam would put Wendy’s range average between 70 and 79 inclusive? Compare to the previous exercise. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179786 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2/3*48+1/3*x<BR>\n" );
document.write( "2/3*48+1/3*x=70<BR>\n" );
document.write( "32+x/3=70<BR>\n" );
document.write( "subtract 32 from both sides<BR>\n" );
document.write( "x/3=38<BR>\n" );
document.write( "x=3*38=114\r<BR>\n" );
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document.write( "32+1/3*x=79<BR>\n" );
document.write( "subtract 32<BR>\n" );
document.write( "x/3=47<BR>\n" );
document.write( "multiply by 3<BR>\n" );
document.write( "x=3*47=141 <BR>\n" );
document.write( "between 114 and 141 inclusive\r<BR>\n" );
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document.write( "If it were 1/3 for the midterm and 2/3 for the final.<BR>\n" );
document.write( "1/3*48+2/3*x=70<BR>\n" );
document.write( "16+2/3x=70<BR>\n" );
document.write( "2x/3=54<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x/3=27<BR>\n" );
document.write( "multiply by 3<BR>\n" );
document.write( "x=3*27=81\r<BR>\n" );
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document.write( "1/3*48+2/3*x=79<BR>\n" );
document.write( "16+2x/3=79<BR>\n" );
document.write( "2x/3=63<BR>\n" );
document.write( "multiply by 3<BR>\n" );
document.write( "2x=189<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x=94.5<BR>\n" );
document.write( "between 81 and 94.5 inclusive\r<BR>\n" );
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document.write( " </SPAN>\n" );
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