document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=246089>Question 246089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help solve:\r<BR>\n" );
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document.write( "(3x+3y+3)/9x  /  (x^2+2xy+y^2-1)/(x^4+x^2)\r<BR>\n" );
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document.write( "I know I can multiply the equation and thus change it to:\r<BR>\n" );
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document.write( "(3x+3y+3)/9x  * (x^4+x^2)/(x^2+2xy+y^2-1)\r<BR>\n" );
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document.write( "Then I am stumped.\r<BR>\n" );
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document.write( "I appreciate the help<BR>\n" );
document.write( "email address had an extra m in .com </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179781 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3x+3y+3)/9x / (x^2+2xy+y^2-1)/(x^4+x^2)<BR>\n" );
document.write( "(3x+3y+3)/9x * (x^4+x^2)/(x^2+2xy+y^2-1)<BR>\n" );
document.write( "NOW YOU CROSS MULTIPLY.<BR>\n" );
document.write( "(3X+3Y+3)(X^4+X^2)/9X(X^2+2XY+Y^2-1) NOW FACTOR THESE TERMS<BR>\n" );
document.write( "3(X+Y+1)X^2(X^2+1)/9X[(X+Y)(X+Y)-1] NOW REDUCE THE FRACTION 3/9 TO 1/3 & THE X TERMS BY X^2/X TO X/1.<BR>\n" );
document.write( "(X+Y+1)X(X^2+1)/3[(X+Y)^2-1]<BR>\n" );
document.write( "X(X+Y+1)(X62+1)/3[X+Y)^2-1] ANS.<BR>\n" );
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