document.write( "Question 246134: Find three consecutive odd integers such that 3 times the largest is 57 more than twice the smallest
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Algebra.Com's Answer #179778 by checkley77(12844)\"\" \"About 
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LET X, X+2 & X+4 BE THE 3 ODD INTEGERS.
\n" ); document.write( "3(X+4)=2X+57
\n" ); document.write( "3X+12=2X+57
\n" ); document.write( "3X-2X=57-12
\n" ); document.write( "X=45 ANS. FOR THE SMALLEST INTEGER.
\n" ); document.write( "45+4=49 ANS. FOR THE LARGEST INTEGER.
\n" ); document.write( "PROOF:
\n" ); document.write( "3*49=2*45+57
\n" ); document.write( "147=90+57
\n" ); document.write( "147=147
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