document.write( "Question 246126: Mary is the younger than her sister Joan. The sum of their age is 15. Twice Joan’s age is three times the sum of 5 and Mary’s age. How old are the two sisters? \n" ); document.write( "
Algebra.Com's Answer #179773 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! M+J=15 OR M=15-J \n" ); document.write( "2J=3(M+5) \n" ); document.write( "2J=3(15-J+5) \n" ); document.write( "2J=3(20-J) \n" ); document.write( "2J=60-3J \n" ); document.write( "2J+3J=60 \n" ); document.write( "5J=60 \n" ); document.write( "J=60/5 \n" ); document.write( "J=12 ANS. JOAN'S AGE. \n" ); document.write( "M=15-12 \n" ); document.write( "M=3 ANS. FOR MARY'S AGE. \n" ); document.write( "PROOF: \n" ); document.write( "2*12=3(3+5) \n" ); document.write( "24=3*8 \n" ); document.write( "24=24\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |