document.write( "Question 246127: Jose, Pedro, and Felipe are brothers and Pedro is the youngest. Felipe is 2 years older than Pedro, and Jose is 3 years older than Felipe. Three times the sum of Pedro and Felipe’s age equals two less than the product of four and Jose’s age. Find the age of all the brothers. \n" ); document.write( "
Algebra.Com's Answer #179764 by marcsam823(57)\"\" \"About 
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Define your terms:\r
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\n" ); document.write( "\n" ); document.write( "Let x = Pedro's age
\n" ); document.write( "Let x + 2 = Felipe's age
\n" ); document.write( "Let x + 5 = Jose's age\r
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\n" ); document.write( "\n" ); document.write( "Translate the words into an algebraic expression:\r
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\n" ); document.write( "\n" ); document.write( "Three times the sum of Pedro and Felipe’s age = two less than the product of four and Jose’s age.\r
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\n" ); document.write( "\n" ); document.write( "3(x + (x + 2)) = 4(x + 5) - 2\r
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\n" ); document.write( "\n" ); document.write( "Solve for x:\r
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\n" ); document.write( "\n" ); document.write( "3(2x + 2) = 4x + 20 - 2
\n" ); document.write( "6x + 6 = 4x +18
\n" ); document.write( "2x = 12\r
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\n" ); document.write( "\n" ); document.write( "x = 6 = Pedro's age
\n" ); document.write( "x + 2 = 8 = Felipe's age
\n" ); document.write( "x + 5 = 11 = Jose's age
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