document.write( "Question 246109: I wrote problem two ways: I think this one however, is the correct one
\n" ); document.write( "f(x)=3x^2 + x - 5\r
\n" ); document.write( "\n" ); document.write( "f(x)=3x^2 + x - 5
\n" ); document.write( "3x^2 + x -5 = 0
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Algebra.Com's Answer #179748 by marcsam823(57)\"\" \"About 
You can put this solution on YOUR website!
Since there is no easy way to factor this equation, use the quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\" \r
\n" ); document.write( "\n" ); document.write( "the general formula for a quadratic is
\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Your equation is:
\n" ); document.write( "\"3x%5E2+%2B+x+-5+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore:
\n" ); document.write( "a=3
\n" ); document.write( "b=1
\n" ); document.write( "c=-5\r
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\n" ); document.write( "\n" ); document.write( "Substitute and solve for x:\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%281%29%2B-+sqrt%28+1%5E2-4%2A3%2A-5%29%29%2F%282%2A3%29+\"\r
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\n" ); document.write( "\"x+=+%28-%281%29%2B-+sqrt%28+1-%28-60%29%29%29%2F6+\" \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%281%29%2B-+sqrt%28+1%2B60%29%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-1+%2B-+sqrt%28+61%29%29%2F6+\"\r
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\n" ); document.write( "\n" ); document.write( "There are 2 answers: (this are the x -coordinates of the points where the parabola crosses the x-axis):
\n" ); document.write( "\"%28-1+%2B+sqrt%2861%29%29%2F6+=+1.135\"
\n" ); document.write( "\"%28-1+-+sqrt%2861%29%29%2F6+=+1.468\"\r
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