document.write( "Question 246080: 3X-2Y=10
\n" ); document.write( "Y=5X-20 \n" ); document.write( "
Algebra.Com's Answer #179731 by richwmiller(17219)\"\" \"About 
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3X-2Y=10
\n" ); document.write( "Y=5X-20
\n" ); document.write( "substituting 5x-20 for y in the first equation
\n" ); document.write( "3x-2(5x-20)=10
\n" ); document.write( "remember minus times a minus is a plus\r
\n" ); document.write( "\n" ); document.write( "3x-10x+40=10
\n" ); document.write( "-7x=-30
\n" ); document.write( "x=-30/-7=(-1)/(-1)*30/7=30/7=4 2/7
\n" ); document.write( "factor second equation
\n" ); document.write( "y=5(x-4)
\n" ); document.write( "substitute 4 2/7
\n" ); document.write( "y=5*(2/7)=10/7\r
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