document.write( "Question 246044: A department store management claims that families spend an average of $630 on gifts during the Christmas season. A sample of 105 families showed that they spent an average of $660 on gifts during the past Christmas season with a standard deviation of $165. Test that the 5% significance level if the mean amount spent on gifts during the holiday by all families is different from $630.(could you please show all 8 steps). \n" ); document.write( "
Algebra.Com's Answer #179721 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A department store management claims that families spend an average of $630 on gifts during the Christmas season. \n" ); document.write( "A sample of 105 families showed that they spent an average of $660 on gifts during the past Christmas season with a standard deviation of $165. \n" ); document.write( "Test at the 5% significance level if the mean amount spent on gifts during the holiday by all families is different from $630. \n" ); document.write( "--------------- \n" ); document.write( "Ho: u = 630 \n" ); document.write( "H1: u is not equal to 630 \n" ); document.write( "---------------------------------- \n" ); document.write( "CV: 2-tail test at 5% with df = 104: t = +/-1.983 \n" ); document.write( "TS: t(660) = (660-630)/[165/sqrt(105)] = 1.8631 \n" ); document.write( "p-value = 2*P(t>1.8631 with df=104) = 2(0.0326) = 0.0653 \n" ); document.write( "---------------------------- \n" ); document.write( "Conclusion: Since the p-value is greater than 5%, fail to \n" ); document.write( "reject Ho. The mean amount spent is different from $630. \n" ); document.write( "============================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |