document.write( "Question 246046: what would the area under the standard normal density curve be with the mean of 0 and the standard deviation of 1?
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Algebra.Com's Answer #179712 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Use the Z-Table Calculator to figure that out.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the top graph\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Enter a mean of 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Enter a standard deviation of 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Select Between\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Enter between -1 and 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It tells you that .682689 proportion of the normal distribution curve is between -1 and 1 which would be plus or minus 1 standard deviation from the mean.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "It also shows you the area under the normal distribution curve that is represented by that proportion.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That's equivalent to 68.2689 percent.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |