document.write( "Question 245966: Can you please tell me if I have this right? If not, can you please explain... Thanks sooo much!\r
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document.write( "Assume a class has 30 members. How many committees of three people can be chosen?\r
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document.write( "I have:
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document.write( "30*29/3=290 \n" );
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Algebra.Com's Answer #179644 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Assume a class has 30 members. How many committees of three people can be chosen? \n" ); document.write( "------------ \n" ); document.write( "30/3 = 10 committees. \n" ); document.write( "--------------------- \n" ); document.write( "If you meant in how many different ways can a committee of 3 be chosen: \n" ); document.write( "The 1 choice is 1 of 30. \n" ); document.write( "Then 1 of 29, then 28. \n" ); document.write( "--> 30*29*28 = 24360. \n" ); document.write( "But, a committee of A, B and C is the same as C, A and B, so it's necessary to divide by 6 (3*2*1 = 6) \n" ); document.write( "-------------------------- \n" ); document.write( "24360/6 = 4060 different combinations. \n" ); document.write( " \n" ); document.write( " |