document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245946>Question 245946</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Quadratic Functions and Equations<BR>\n" );
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document.write( "The first question I gave it go at.<BR>\n" );
document.write( "Solve.<BR>\n" );
document.write( "3t^2-2=0<BR>\n" );
document.write( "     +2+2<BR>\n" );
document.write( "3t^2=2<BR>\n" );
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document.write( "3      3<BR>\n" );
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document.write( "t^2=2/3 or (I don't know how to do the square root sign on here.)<BR>\n" );
document.write( "_  ______            _    _   __________<BR>\n" );
document.write( "  V2/3          or             V 2/3<BR>\n" );
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document.write( "Hope I did it right.<BR>\n" );
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document.write( "Then the next is also solve.<BR>\n" );
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document.write( "x^2+7=3x<BR>\n" );
document.write( "Now so far all I have done is taken 3x from both sides<BR>\n" );
document.write( "which brings us to<BR>\n" );
document.write( "x^2-3x+7=0<BR>\n" );
document.write( "At this point I am lost. Because normally I would think we would do this but I can't find anything to add up to equal 3<BR>\n" );
document.write( "(x    )(x   )=0<BR>\n" );
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document.write( "So I am stuck with this problem.<BR>\n" );
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document.write( "Last problem I am having is one that I got so confused w/ the process that I couldn't even start it. I am just lost.<BR>\n" );
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document.write( "It states:<BR>\n" );
document.write( "For each quadratic function, (a) find the vertex and the axis of symmetry and (b) graph the function.<BR>\n" );
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document.write( "g(x)=2x^2+5x-1<BR>\n" );
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document.write( "I know we follow the form of  a(x-h)^2+k. But I am so lost at this. I know it is most likely real easy but I am lost. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179618 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179618\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you should only have one problem per entry.<BR>\n" );
document.write( "Sqrt is the symbol for square root<BR>\n" );
document.write( "So you should have plus or minus Sqrt (2/3) is correct\r<BR>\n" );
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document.write( "x^2+7=3x<BR>\n" );
document.write( "Now so far all I have done is taken 3x from both sides<BR>\n" );
document.write( "which brings us to<BR>\n" );
document.write( "x^2-3x+7=0<BR>\n" );
document.write( "At this point I am lost. Because normally I would think we would do this but I can't find anything to add up to equal 3<BR>\n" );
document.write( "so you have to use another method<BR>\n" );
document.write( "the quadratic formula or complete the square<BR>\n" );
document.write( "I will show you complete the square.<BR>\n" );
document.write( "so we rearrange the equation.<BR>\n" );
document.write( "x^2-3x=-7<BR>\n" );
document.write( "take half of -3 and square it<BR>\n" );
document.write( "(3/2)^2=9/4<BR>\n" );
document.write( "add 9/4 to both sides\r<BR>\n" );
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document.write( "x^2-3x+9/4=-28/4+(9/4)=-19/4<BR>\n" );
document.write( "X^2-3x+9/4=-19/4\r<BR>\n" );
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document.write( "factor the left side<BR>\n" );
document.write( "(x-3/2)^2=-19/4<BR>\n" );
document.write( "now we see we will be dealing with imaginary numbers since we need to get the sqrt of a minus number<BR>\n" );
document.write( "get he sqrt of both sides<BR>\n" );
document.write( "|x-3/2|=(i*sqrt(19))/2\r<BR>\n" );
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document.write( "x=3/2+-(i*sqrt(19))/2\r<BR>\n" );
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document.write( "x=1/2(3-i*sqrt19)\r<BR>\n" );
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document.write( "x=1/2(3+i*sqrt19)\r<BR>\n" );
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