document.write( "Question 245814: I need help w/step by step instruction on how to solve this word problem.\r
\n" ); document.write( "\n" ); document.write( "The speed of a boat in still water is 10 km/h. The boat travels 48km upstream and 48km downstream in a total time of 10 hr. What is the speed of the stream?\r
\n" ); document.write( "\n" ); document.write( "I think I know the answer but am unsure of how to show it, step by step, in an algebraic equation.\r
\n" ); document.write( "\n" ); document.write( "Thanks! \n" ); document.write( "
Algebra.Com's Answer #179575 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
The speed of a boat in still water is 10 km/h. The boat travels 48km upstream and 48km downstream in a total time of 10 hr. What is the speed of the stream?
\n" ); document.write( "----------------
\n" ); document.write( "Use the d = rt, distance = rate x time.
\n" ); document.write( "d = rt
\n" ); document.write( "t = d/r
\n" ); document.write( "r = rate of the boat
\n" ); document.write( "c = speed of the current
\n" ); document.write( "----------------
\n" ); document.write( "Upstream, t = 48/(r-c) current subtracted from boat speed
\n" ); document.write( "Downstream, t = 48/(r+c)
\n" ); document.write( "48/(10-c) + 48/(10+c) = 10
\n" ); document.write( "Now it's just another equation.
\n" ); document.write( "48(10+c) + 48(10-c) = 10*(10+c)*(10-c)
\n" ); document.write( "960 = 1000 - 10c^2
\n" ); document.write( "c^2 = 4
\n" ); document.write( "c = 2 km/hr
\n" ); document.write( " \n" ); document.write( "
\n" );