document.write( "Question 245875: Please help me with this word problem!\r
\n" ); document.write( "\n" ); document.write( "Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
\n" ); document.write( "L. Karina
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Algebra.Com's Answer #179556 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking?
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\n" ); document.write( "2nd cyclist DATA:
\n" ); document.write( "rate = 10 mph ; time = x hrs ; distance = rt = 10x miles
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\n" ); document.write( "1st cyclist DATA:
\n" ); document.write( "rate = 6 mph ; time = x+3 hrs ; distance = rt = 6(x+3) miles
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\n" ); document.write( "Equation:
\n" ); document.write( "distance = distance
\n" ); document.write( "10x = 6x+18
\n" ); document.write( "4x = 18
\n" ); document.write( "x = 9.2 = 4.5 hrs (time for the 2nd to catch up to the 1st)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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