document.write( "Question 245863: Solve by applying the Quadratic Formula. Show your work. thanks\r
\n" ); document.write( "\n" ); document.write( "4x^2 + 48x + 104 = 0
\n" ); document.write( "

Algebra.Com's Answer #179536 by College Student(505)\"\" \"About 
You can put this solution on YOUR website!
A quadratic equation would look like this: \"Ax%5E2%2BBx%2BC=0\"
\n" ); document.write( "And a quadratic formula would look like this: \"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\"
\n" ); document.write( ".
\n" ); document.write( "So, for the following quadratic equation: \"4x%5E2%2B48x%2B104=0\"
\n" ); document.write( "Its quadratic formula would be:
\n" ); document.write( "\"x=%28-48%2B-sqrt%2848%5E2-%284%284%2A104%29%29%29%29%2F%282%2A4%29\"
\n" ); document.write( "Now work the algebra and solve for x:
\n" ); document.write( "\"x=%28-48%2B-sqrt%2848%5E2-%284%28416%29%29%29%29%2F%288%29\"
\n" ); document.write( ".
\n" ); document.write( "\"x=%28-48%2B-sqrt%2848%5E2-1664%29%29%2F%288%29\"
\n" ); document.write( ".
\n" ); document.write( "\"x=%28-48%2B-sqrt%282304-1664%29%29%2F%288%29\"
\n" ); document.write( ".
\n" ); document.write( "\"x=%28-48%2B-sqrt%28640%29%29%2F%288%29\"
\n" ); document.write( ".
\n" ); document.write( "Notice -48/8=-6, so:
\n" ); document.write( ".
\n" ); document.write( "\"x=-6%2B-sqrt%28640%29\"
\n" ); document.write( ".
\n" ); document.write( "\"x=-6%2B-sqrt%2864%2A10%29\"
\n" ); document.write( ".
\n" ); document.write( "\"x=-6%2B8sqrt%2810%29\" ...and... \"x=-6-8sqrt%2810%29\"
\n" ); document.write( ".
\n" ); document.write( "We may simplify them further if you want to use decimals.
\n" ); document.write( "If so, use your calculator to find the square root of 10 and perform the math.
\n" ); document.write( "Otherwise, the above answers would suffice. :)
\n" ); document.write( "
\n" );