document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245861>Question 245861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem.\r<BR>\n" );
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document.write( "An object is thrown downward from a plane which is 540 feet above the ground. The object is thrown with an initial velocity of 27 ft/sec. The distance traveled by the object in t seconds is s = 16t2 + 27t, where s is in feet. How long does it take the object to reach the ground? Show your work. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179532 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179532\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the plane is 540 feet above the ground, s is 540 so we have:\r<BR>\n" );
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document.write( "540 = 16t^2 + 27t or<BR>\n" );
document.write( "16t^2 + 27t - 540 = 0\r<BR>\n" );
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document.write( "Solve for t. One way to do this would be to use the quadratic formula where a=16, b=27 and c=-540.   </SPAN>\n" );
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