document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245692>Question 245692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The shortest side of an isosceles triangle is 23 cm less than twice as long as the other sides. The perimeter of the triangle is 41 cm. Find the lengths of the three sides </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179526 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179526\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An isosceles triangle has two sides that are equal.<BR>\n" );
document.write( "so the perimeter=2L+B where L=equals one of the equal sides and b= the base<BR>\n" );
document.write( "2L+B=41 cm.<BR>\n" );
document.write( "B=2L-23cm.<BR>\n" );
document.write( "so we can substitute 2L-23 for B<BR>\n" );
document.write( "2L+2L-23=41<BR>\n" );
document.write( "4L-23=41<BR>\n" );
document.write( "add 23 to both sides<BR>\n" );
document.write( "4L=64<BR>\n" );
document.write( "divide both sides by 4<BR>\n" );
document.write( "L=16<BR>\n" );
document.write( "B=2L-23<BR>\n" );
document.write( "B=2*(16)-23<BR>\n" );
document.write( "B=32-23<BR>\n" );
document.write( "B=9<BR>\n" );
document.write( "So we have 16 cm., 16 cm. , and 9 cm.<BR>\n" );
document.write( "check<BR>\n" );
document.write( "16+16+9=41<BR>\n" );
document.write( "41=41\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );