document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=243876>Question 243876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The unit of measure for a line is in inches. Use the distance formula to find the length of the line with points at (- 3, 0) and (4, 3). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179521 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c^2=a^2+b^2<BR>\n" );
document.write( "is the formula for finding the hypotenuse of a right triangle.\r<BR>\n" );
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document.write( "Think of the points as the ends of the hypotenuse of a right triangle.<BR>\n" );
document.write( "one leg (x) of the triangle goes from 4 to -3<BR>\n" );
document.write( "so we subtract -3 from 4<BR>\n" );
document.write( "and the other leg (y) goes from 3 to 0<BR>\n" );
document.write( "so we subtract 0 from 3<BR>\n" );
document.write( "so first we need to find the length of each leg of the triangle<BR>\n" );
document.write( "where a=4-(-3)=7<BR>\n" );
document.write( "and b=3-0=3<BR>\n" );
document.write( "substitute<BR>\n" );
document.write( "c^2=7^2+3^2<BR>\n" );
document.write( "calculate squares<BR>\n" );
document.write( "c^2=49+9<BR>\n" );
document.write( "add<BR>\n" );
document.write( "c^2=58<BR>\n" );
document.write( "find square root<BR>\n" );
document.write( "c=sqrt(58)= abt 7.6 inches </SPAN>\n" );
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