document.write( "Question 245847: How do a use the quadratic formula to solve this partial equation..\r
\n" ); document.write( "\n" ); document.write( "(4x+1)^2 = 3x+4
\n" ); document.write( "

Algebra.Com's Answer #179509 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"%284x%2B1%29%5E2+=+3x%2B4\"
\n" ); document.write( "To use the quadratic formula, \"x+=+%28-b+%2B-+sqrt%28b%5E2+-+4ac%29%29%2F2a\", your equation needs to be in \"ax%5E2+%2B+bx+%2B+c+=+0\" form. So getting the equation into the proper form is where we start.
\n" ); document.write( "Multiply out the left side:
\n" ); document.write( "\"16x%5E2+%2B+8x+%2B+1+=+3x+%2B+4\"
\n" ); document.write( "Make the right side zero by subtracting 3x and 4 from each side:
\n" ); document.write( "\"16x%5E2+%2B+5x+-+3+=+0\"
\n" ); document.write( "Now we have the proper form and we can use the quadratic formula with \"a\" = 16, \"b\" = 5 and \"c\" = -3:
\n" ); document.write( "\"x+=+%28-%285%29+%2B-+sqrt%28%285%29%5E2+-+4%2816%29%28-3%29%29%29%2F2%2816%29\"
\n" ); document.write( "Now we simplify:
\n" ); document.write( "\"x+=+%28-%285%29+%2B-+sqrt%2825+-+4%2816%29%28-3%29%29%29%2F2%2816%29\"
\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%2825+%2B+192%29%29%2F32\"
\n" ); document.write( "\"x+=+%28-5+%2B-+sqrt%28217%29%29%2F32\"
\n" ); document.write( "So
\n" ); document.write( "\"x+=+%28-5+%2B+sqrt%28217%29%29%2F32\" or \"x+=+%28-5+-+sqrt%28217%29%29%2F32\"
\n" ); document.write( "
\n" );