document.write( "Question 245670: Four years ago, Katie was twice as old as Anne was then. In 6 years, Anne will be the same age that katie is now. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #179505 by College Student(505)![]() ![]() You can put this solution on YOUR website! Four years ago: \n" ); document.write( "Anne = x \n" ); document.write( "Katie = 2x \n" ); document.write( ". \n" ); document.write( "Today (four years later) \n" ); document.write( "Anne = x+4 \n" ); document.write( "Katie = 2x+4 \n" ); document.write( ". \n" ); document.write( "In six years Anne will be the same age Katie is now. So our equation becomes: \n" ); document.write( " \n" ); document.write( "Combine like terms and solve for x to find today's Anne's age. \n" ); document.write( "I'll let you take it from here. :) \n" ); document.write( " |