document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245825>Question 245825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I do not understand how to write an equation of a line passing through a point with an already given slope.\r<BR>\n" );
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document.write( "Ex. (3,-4); m=2/3<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179492 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179492\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of a line in slope intercept form is:\r<BR>\n" );
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document.write( "y = m*x + b where m is the slope and b is the value of y where the line crosses the y-axis (this is actually the value of y when x is zero).\r<BR>\n" );
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document.write( "Since you know the slope m in this case is 2/3 you have: \r<BR>\n" );
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document.write( "y = (2/3)*x + b\r<BR>\n" );
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document.write( "Since the point (3,-4) is a point on the line we know that:\r<BR>\n" );
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document.write( "-4 = (2/3)*3 + b\r<BR>\n" );
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document.write( "-4 = 2 + b<BR>\n" );
document.write( "-2 = b\r<BR>\n" );
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document.write( "Substituting -2 for b in the equation above we get:\r<BR>\n" );
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document.write( "y = (2/3)*x -2 for the equation of the line  </SPAN>\n" );
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