document.write( "Question 31270: The height of a triangle is 4m more than twice the length of the base. the area is 35m2. I know that A=1/2BH, but I just can't put it into an equation to work it. \n" ); document.write( "
Algebra.Com's Answer #17944 by troyapplehelen(46)\"\" \"About 
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1. h=2b+4, and A=(1/2)b.h
\n" ); document.write( " =(1/2)b(2b+4)=35
\n" ); document.write( " A is (b^2)+(4b)=70
\n" ); document.write( " 2(b^2) + 4b -70 =0
\n" ); document.write( " =b^2 +2b -35 =0
\n" ); document.write( " (b+7)(b-5) = 0 so, b is -7 or 5 but -7 is not exist in
\n" ); document.write( " length so we chose b=5 only.
\n" ); document.write( " then, ur area 35 = (1/2)5.14 works.
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