document.write( "Question 31270: The height of a triangle is 4m more than twice the length of the base. the area is 35m2. I know that A=1/2BH, but I just can't put it into an equation to work it. \n" ); document.write( "
Algebra.Com's Answer #17944 by troyapplehelen(46) ![]() You can put this solution on YOUR website! 1. h=2b+4, and A=(1/2)b.h \n" ); document.write( " =(1/2)b(2b+4)=35 \n" ); document.write( " A is (b^2)+(4b)=70 \n" ); document.write( " 2(b^2) + 4b -70 =0 \n" ); document.write( " =b^2 +2b -35 =0 \n" ); document.write( " (b+7)(b-5) = 0 so, b is -7 or 5 but -7 is not exist in \n" ); document.write( " length so we chose b=5 only. \n" ); document.write( " then, ur area 35 = (1/2)5.14 works. \n" ); document.write( " |