document.write( "Question 245368: \r
\n" ); document.write( "\n" ); document.write( "A sister while growing up was 5 times her brothers age, then she was 4 times, then 3 times, now she is 2 times his age………\r
\n" ); document.write( "\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "How old are the brother and sister now??????????????
\n" ); document.write( "

Algebra.Com's Answer #179418 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A sister while growing up was 5 times her brothers age, then she was 4 times, then 3 times, now she is 2 times his age………
\n" ); document.write( ":
\n" ); document.write( "Here's what I get, but having trouble getting a formula to find this:
\n" ); document.write( ":
\n" ); document.write( "Sis|bro|mult
\n" ); document.write( "---|---|----
\n" ); document.write( "15 | 3 * 5
\n" ); document.write( "16 | 4 * 4
\n" ); document.write( "18 | 6 * 3
\n" ); document.write( "24 | 12 * 2; their ages now
\n" ); document.write( ":
\n" ); document.write( "If I come up with a formula for this I will edit this solution\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );