document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245657>Question 245657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 72 m. If the width were doubled and the lengh were increased by 9 m, then the perimeter would be 114 m. What are the dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179396 by </B><A HREF=/tutors/aboutme.mpl?userid=TheProdicalSon><B>TheProdicalSon(34)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=TheProdicalSon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179396\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2w + 2l = 72<BR>\n" );
document.write( "2h + 2l+18 = 114<BR>\n" );
document.write( "-18           -18<BR>\n" );
document.write( "2h + 2l = 96<BR>\n" );
document.write( "(96 - 72 = 24)<BR>\n" );
document.write( "2h = 24<BR>\n" );
document.write( "h = 12<BR>\n" );
document.write( "w = 12<BR>\n" );
document.write( "24 + 2l = 72<BR>\n" );
document.write( "2l = 48<BR>\n" );
document.write( "l = 24\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "length is 24<BR>\n" );
document.write( "width is 12 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );