document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245618>Question 245618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the perimeter of the rectangle is 56 feet, find its area. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179393 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=3W<BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "56=2*3W+2W<BR>\n" );
document.write( "56=6W+2W<BR>\n" );
document.write( "8W=56<BR>\n" );
document.write( "W=56/8<BR>\n" );
document.write( "W=7 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=3*7=21 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "56=2*21+2*7<BR>\n" );
document.write( "56=42+14<BR>\n" );
document.write( "56=56<BR>\n" );
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