document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31203>Question 31203</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please find the equation of the line that passes through (2,1) and is parallel to the line: 4x-2y=3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17935 by </B><A HREF=/tutors/aboutme.mpl?userid=troyapplehelen><B>troyapplehelen(46)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=troyapplehelen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. 4x-2y=3 can be rewritten as 4x-3=2y, y=(4x)/2-(3/2)<BR>\n" );
document.write( "   according line equation, y=mx+b, the slope of line m=2(from 4x/2)<BR>\n" );
document.write( "   if the line is parallel to the original, the the slope shoulb the same so, the new line equation is y=2x+b.<BR>\n" );
document.write( "2. now, find \"b\" by substituting (2,1) into the new line formular y=2x+b.<BR>\n" );
document.write( "   like, 1=(2 times 2)+b, then \"b\" is -3.<BR>\n" );
document.write( "3. so, the answer is y=2x-3.  </SPAN>\n" );
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