document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245428>Question 245428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with the following problem:\r<BR>\n" );
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document.write( "Let f(x) {= 3x^2 - x+1, x < 5<BR>\n" );
document.write( "                 -4x-3, x>5 (the arrow is underscored)\r<BR>\n" );
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document.write( "a) f(6)<BR>\n" );
document.write( "b  f(0)<BR>\n" );
document.write( "c) f(-3) <BR>\n" );
document.write( "         <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179313 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179313\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since 6 is greater than 5 use f(x) = -4*x-3  <BR>\n" );
document.write( "f(6) = -4*6 - 3 = ?\r<BR>\n" );
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document.write( "Since 0 is less than 5 use f(x) = 3x^2 - x + 1<BR>\n" );
document.write( "f(0) = 3*(0^2) - 0 + 1 = ?\r<BR>\n" );
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document.write( "Since -3 is less than 5 use f(x) = 3x^2 - x + 1<BR>\n" );
document.write( "f(-3) = 3*(-3)^2 - (-3) + 1 = ? </SPAN>\n" );
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