document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31245>Question 31245</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help my homework is due today\r<BR>\n" );
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document.write( "-3(-4x^-6)-2\r<BR>\n" );
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document.write( "and also<BR>\n" );
document.write( "x^7y^-4<BR>\n" );
document.write( "_________<BR>\n" );
document.write( "   -2x^-2<BR>\n" );
document.write( "and all has large bracket around entire problem and ^of -3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17931 by </B><A HREF=/tutors/aboutme.mpl?userid=troyapplehelen><B>troyapplehelen(46)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=troyapplehelen><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17931\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in second problem, y^(-4) is 1/y^4 or bring it down to the denominator as y^4.<BR>\n" );
document.write( "also, x^(-2) is 1/x^2 or bring it up to the numerator as x^2.<BR>\n" );
document.write( "then rewrite it as {(x^7)(x^2)}/-2(y^4).<BR>\n" );
document.write( "and the powering with -3, is (positive 3rd power) of its reciprocal.<BR>\n" );
document.write( "so, [{-2(y^4)}^3]/(x^9)^3 </SPAN>\n" );
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