document.write( "Question 245426: Ed is 1/5 as old as laura. In 6 years, ed's age will be 3 years more than 1/4 of laura's age. How old are ed and laura now? \n" ); document.write( "

Algebra.Com's Answer #179302 by College Student(505) $\"\"$ $\"About$

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Let Laura = x
\n" ); document.write( "Let Ed = x/5
\n" ); document.write( ".
\n" ); document.write( "In 6 years, ed's age will be 3 years more than 1/4 of laura's age.
\n" ); document.write( "Thus our equation becomes:
\n" ); document.write( " $\"%28x%2F5%29%2B6=%28%28x%2B6%29%2F4%29%2B3\"$
\n" ); document.write( "Combine like terms:
\n" ); document.write( " $\"%28x%2F5%29-%28%28x%2B6%29%2F4%29=3-6\"$
\n" ); document.write( "Find common denominator
\n" ); document.write( " $\"%28%28x%2F5%29%284%2F4%29%29-%28%28%28x%2B6%29%2F4%29%285%2F5%29%29=-3\"$
\n" ); document.write( " $\"%284x%2F20%29-%28%285%28x%2B6%29%29%2F20%29=-3\"$
\n" ); document.write( "Now simplify and solve for x.
\n" ); document.write( "I'll let you take it from here.
\n" ); document.write( "You should come up with x=30 (Laura's age).
\n" ); document.write( "Remember to check your answer by pluging this value in the original equation.
\n" ); document.write( "Both sides of the equation must equal to each other to be a valid answer.
\n" ); document.write( "Done! :) \n" ); document.write( "

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