document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245447>Question 245447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A pyramid with a square base has an area of 890 square meters. The height of the pyramid is 11 meters.\r<BR>\n" );
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document.write( "What is the volume of the pyramid?\r<BR>\n" );
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document.write( "Round your answer to the nearest whole number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179296 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179296\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the total surface area of a pyramid, use this equation:\r<BR>\n" );
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document.write( "Surface Area = B + 1/2 * P * s\r<BR>\n" );
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document.write( "B = base area<BR>\n" );
document.write( "P = perimeter of the base<BR>\n" );
document.write( "s = slant height\r<BR>\n" );
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document.write( "To find the volume of a Pyramid, substitute into this equation:\r<BR>\n" );
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document.write( "V=1/3Bh\r<BR>\n" );
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document.write( "B=base area<BR>\n" );
document.write( "h=height of pyramid<BR>\n" );
document.write( " </SPAN>\n" );
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