document.write( "Question 245451: Find three consecutive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer. \n" ); document.write( "
Algebra.Com's Answer #179292 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the first integer.\r
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\n" ); document.write( "\n" ); document.write( "Then is the next consecutive integer. But if is even, then , must be odd. Therefore, the next consecutive even integer must be .\r
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\n" ); document.write( "\n" ); document.write( "It follows then that the next consecutive integer after that must be \r
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\n" ); document.write( "\n" ); document.write( "Square the first integer: \r
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\n" ); document.write( "\n" ); document.write( "Square the second integer: \r
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\n" ); document.write( "\n" ); document.write( "Add these two quantities: \r
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\n" ); document.write( "\n" ); document.write( "And this sum is equal to the square of the third integer:\r
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\n" ); document.write( "\n" ); document.write( "Collect like terms in the LHS, leaving the RHS equal to zero:\r
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\n" ); document.write( "\n" ); document.write( "Now solve the factorable quadratic. Each of the roots will be the first of a series of three consecutive even integers that fit the parameters of the problem. Remember that 0 is a perfectly good even integer in this context.\r
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