document.write( "Question 245464: I am trying to figure out how to figure the sum of a cube...125r^3+1. I am coming up with (x^2+5r+25r^2)(1+5r) but I am not sure it is correct. Can anyone help me? Thanks \n" ); document.write( "

Algebra.Com's Answer #179290 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Factor:
\n" ); document.write( " $\"125r%5E3%2B1\"$ As you have pointed out, this is the sum of two cubes:
\n" ); document.write( " $\"%285r%29%5E3%2B%281%29%5E3\"$
\n" ); document.write( "The sum of two cubes is factored thus:
\n" ); document.write( " $\"A%5E3%2BB%5E3+=+%28A%2BB%29%28A%5E2-AB%2BB%5E2%29\"$ and here, $\"A+=+5r\"$ , $\"B+=+1\"$ , so...
\n" ); document.write( " $\"125r%5E3%2B1+=+%285r%2B1%29%2825r%5E2-5r%2B1%29\"$ \n" ); document.write( "

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