document.write( "Question 245438: Solve for x:
\n" ); document.write( "5x^2=-17x-6\r
\n" ); document.write( "\n" ); document.write( "I have no idea where to begin. Thanks. \n" ); document.write( "
Algebra.Com's Answer #179276 by richwmiller(17219)\"\" \"About 
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5x^2=-17x-6
\n" ); document.write( "we want to put it in the style of
\n" ); document.write( "ax^2+bx+c=0
\n" ); document.write( "to move everything to one side we add 17x+6 to both sides
\n" ); document.write( "5x^2+17x+6=0
\n" ); document.write( "I suggest formula the quadratic formula
\n" ); document.write( "x=-b+-sqrt(b^2-4ac)/(2*a)
\n" ); document.write( "where a=5; b=17 and c=6
\n" ); document.write( "so we get b^2-4ac=17^2-4*5*6
\n" ); document.write( "Since 17^2-4*5*6 is greater than zero we will have two solutions.
\n" ); document.write( "continue plugging in the values a;b and c
\n" ); document.write( "the two solutions are
\n" ); document.write( "(-17+sqrt(17^2-4*5*6))/2*5
\n" ); document.write( "(-17-sqrt(17^2-4*5*6))/2*5\r
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