document.write( "Question 245404: The length of a rectangle is 4 times the width. The perimeter is 200 ft. Find the length & width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #179268 by richwmiller(17219)\"\" \"About 
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The length of a rectangle is 4 times the width. The perimeter is 200 ft. Find the length & width of the rectangle.
\n" ); document.write( "What do we know?
\n" ); document.write( "We know the outside of the rectangle (Perimeter) is 200ft.
\n" ); document.write( "Let P=200
\n" ); document.write( "what is the formula for the perimeter?
\n" ); document.write( "L+L+W+W=Perimeter\r
\n" ); document.write( "\n" ); document.write( "We also know that L=4W
\n" ); document.write( "So now we can substitute 4W for every L in the equation
\n" ); document.write( "so we have
\n" ); document.write( "4W+4W+W+W=200
\n" ); document.write( "10W=200
\n" ); document.write( "W=20 Ft.
\n" ); document.write( "4W=80 Ft.=L
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