document.write( "Question 245404: The length of a rectangle is 4 times the width. The perimeter is 200 ft. Find the length & width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #179268 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 4 times the width. The perimeter is 200 ft. Find the length & width of the rectangle. \n" ); document.write( "What do we know? \n" ); document.write( "We know the outside of the rectangle (Perimeter) is 200ft. \n" ); document.write( "Let P=200 \n" ); document.write( "what is the formula for the perimeter? \n" ); document.write( "L+L+W+W=Perimeter\r \n" ); document.write( "\n" ); document.write( "We also know that L=4W \n" ); document.write( "So now we can substitute 4W for every L in the equation \n" ); document.write( "so we have \n" ); document.write( "4W+4W+W+W=200 \n" ); document.write( "10W=200 \n" ); document.write( "W=20 Ft. \n" ); document.write( "4W=80 Ft.=L \n" ); document.write( " \n" ); document.write( " |