document.write( "Question 244899: Diophantus spent 1/6 of his life in childhood, 1/12 as a youth, and 1/7 more as a bachelor. 5 years after his marriage was born a son who died 4 years before his father at 1/2 the age at which his father died. How old was Diophantus when he died?
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Algebra.Com's Answer #179223 by ankor@dixie-net.com(22740)\"\" \"About 
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Diophantus spent 1/6 of his life in childhood, 1/12 as a youth, and 1/7 more as a bachelor. 5 years after his marriage was born a son who died 4 years before his father at 1/2 the age at which his father died. How old was Diophantus when he died?\r
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\n" ); document.write( "Let x = his final age
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\n" ); document.write( "a lengthy but simple equation
\n" ); document.write( "Final age = child + youth + bach + marriage + son's age + 4
\n" ); document.write( "x = \"1%2F6\"x + \"1%2F12\"x + \"1%2F7\"x + 5 + \"1%2F2\"x + 4
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\n" ); document.write( "Common denominator of 12*7 = 84
\n" ); document.write( "x = \"14%2F84\"x + \"7%2F84\"x + \"12%2F84\"x + 5 + \"42%2F84\"x + 4
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\n" ); document.write( "x = \"75%2F84\"x + 9
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\n" ); document.write( "\"84%2F84\"x - \"75%2F84\"x = 9
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\n" ); document.write( "\"9%2F84\"x = 9
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\n" ); document.write( "x = 84 is his final age
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\n" ); document.write( "Check:
\n" ); document.write( "14 + 7 + 12 + 5 + 42 + 4 = 84
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