document.write( "Question 244899: Diophantus spent 1/6 of his life in childhood, 1/12 as a youth, and 1/7 more as a bachelor. 5 years after his marriage was born a son who died 4 years before his father at 1/2 the age at which his father died. How old was Diophantus when he died?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #179223 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Diophantus spent 1/6 of his life in childhood, 1/12 as a youth, and 1/7 more as a bachelor. 5 years after his marriage was born a son who died 4 years before his father at 1/2 the age at which his father died. How old was Diophantus when he died?\r \n" ); document.write( "\n" ); document.write( ": \n" ); document.write( "Let x = his final age \n" ); document.write( ": \n" ); document.write( "a lengthy but simple equation \n" ); document.write( "Final age = child + youth + bach + marriage + son's age + 4 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "Common denominator of 12*7 = 84 \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( "x = \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "x = 84 is his final age \n" ); document.write( ": \n" ); document.write( "Check: \n" ); document.write( "14 + 7 + 12 + 5 + 42 + 4 = 84 \n" ); document.write( " |