document.write( "Question 245261: the length of a rectangle is 5 more than twice it's width. its perimeter is 88 feet. find it's dimensions \n" ); document.write( "
Algebra.Com's Answer #179221 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 2L + 2W = 88 \n" ); document.write( "L + W = 44 \n" ); document.write( "L = 2W + 5 \n" ); document.write( "---------- \n" ); document.write( "Sub for L into line 2 \n" ); document.write( "(2W+5) + W = 44 \n" ); document.write( "3W = 39 \n" ); document.write( "W = 13 \n" ); document.write( "L = 31 \n" ); document.write( "------ \n" ); document.write( "PS it's = it is. \n" ); document.write( " the length of a rectangle is 5 more than twice its width. its perimeter is 88 feet. find its dimensions\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |