document.write( "Question 245167: The perimeter of a rectangle is six times the width. If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. What are the length and the width? \n" ); document.write( "
Algebra.Com's Answer #179206 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is six times the width. \n" ); document.write( ": \n" ); document.write( "perimeter: \n" ); document.write( "2L + 2W = 6W \n" ); document.write( "2L = 6W - 2W \n" ); document.write( "2L = 4W \n" ); document.write( "Simplify, divide both sides by 2 \n" ); document.write( "L = 2W \n" ); document.write( ": \n" ); document.write( "If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. \n" ); document.write( "2(L+4) + 2(W+7) = 160 \n" ); document.write( "2L + 8 + 2W + 14 = 160 \n" ); document.write( "2L + 2W + 22 = 160 \n" ); document.write( "2L + 2W = 160 - 22 \n" ); document.write( "2L + 2W = 138 \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "L + W = 69 \n" ); document.write( ": \n" ); document.write( " What are the length and the width? \n" ); document.write( "From the 1st statement we know L=2W; replace L with 2W \n" ); document.write( "2W + W = 69 \n" ); document.write( "3W = 69 \n" ); document.write( "W = \n" ); document.write( "W = 23 is the width \n" ); document.write( "then \n" ); document.write( "L = 2(23) \n" ); document.write( "L = 46 is the width \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in the 1st statement: \n" ); document.write( "\"The perimeter of a rectangle is six times the width.\" \n" ); document.write( "2(46) + 2(23) = 6(23) \n" ); document.write( "92 + 46 = 138; \n" ); document.write( ": \n" ); document.write( "YOu can check the solution using the 2nd statement \n" ); document.write( "\"If the length were increased by 4 inches and the width were increased by 7 inches, then the perimeter would be 160 inches. \" \n" ); document.write( " |