document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=245058>Question 245058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> suppose that the width of a rectangle is three feet shorter than lenght and that the perimeter of the rectangle is 84 feet.<BR>\n" );
document.write( "a.)set up an equation for the perimeter involving only L, the leght of the rectangle.<BR>\n" );
document.write( "b.)solce the equation algebraically to find the lenght of the rectangle.find the width as well. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179182 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=L-3<BR>\n" );
document.write( "2L+2W=84<BR>\n" );
document.write( "2L+2(L-3)=84<BR>\n" );
document.write( "2L+2L-6=84<BR>\n" );
document.write( "4L=84+6<BR>\n" );
document.write( "4L=90<BR>\n" );
document.write( "L=90/4<BR>\n" );
document.write( "L=22.5 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "W=22.5-3=19.5 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*22.5+2*19.5<BR>\n" );
document.write( "45+39=84<BR>\n" );
document.write( "84=84\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );