document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244979>Question 244979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a perimeter of 160' and the width is x and the lenght is 2x-10. What would the area also be. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179174 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179174\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2W+2L=perimeter.<BR>\n" );
document.write( "2x+2(2x-10)=160<BR>\n" );
document.write( "2x+4x-20=160<BR>\n" );
document.write( "6x=160+20<BR>\n" );
document.write( "6x=180<BR>\n" );
document.write( "x=180/6<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "2*30=60 for the width.<BR>\n" );
document.write( "2*30-20=60-20=40 for the length.<BR>\n" );
document.write( "Area=LW<BR>\n" );
document.write( "Area=60*40=2,400 ans. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );