document.write( "Question 244998: given log(base a)x=4, log(base a)y=3, and log(base a)z=2 for constants x, y,z. find the value of the logarithm.\r
\n" ); document.write( "\n" ); document.write( "log(base a)((5th root of y^3 times x^6 times z^4)/(5th root of z^6 times x^2)
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Algebra.Com's Answer #179123 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
you are given:\r
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\n" ); document.write( "\n" ); document.write( "log(a,x) = 4
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\n" ); document.write( "\n" ); document.write( "you want to find:\r
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\n" ); document.write( "\n" ); document.write( "since \"root%28n%2Ca%29%2Froot%28n%2Cb%29+=+root%28n%2C%28a%2Fb%29%29\", your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%28a%2C%28%28root%285%2C%28y%5E3%2Ax%5E6%2Az%5E4%29%2F%28z%5E6%2Ax%5E2%29%29%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "since \"root%285%2Ca%29+=+a%5E%281%2F5%29\", your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"log%28a%2C%28%28%28y%5E3%2Ax%5E6%2Az%5E4%29%2F%28z%5E6%2Ax%5E2%29%29%5E%281%2F5%29%29%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "since log(a^b) = b*(log(a), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "since log(a/b) = log(a)/log(b), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "since log(a*b) = log(a) + log(b), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "since log(a^b) = b*log(a), your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "from here on it's just a straight substitution since you are given:\r
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\n" ); document.write( "\n" ); document.write( "log(a,x) = 4
\n" ); document.write( "log(a,y) = 3
\n" ); document.write( "log(a,z) = 2\r
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\n" ); document.write( "\n" ); document.write( "your equation of:\r
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\n" ); document.write( "\n" ); document.write( "becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F5%29+%2A+%283%2A3+%2B+6%2A4+%2B+4%2A2+-+6%2A2+-+2%2A4%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F5%29+%2A+%289%2B24%2B8-12-8%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F5%29+%2A+%2821%29\" which becomes:\r
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\n" ); document.write( "\n" ); document.write( "\"21%2F5\"\r
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