document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244940>Question 244940</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Multiply\r<BR>\n" );
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document.write( "square root 7 (square root 5 - square root 3) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179117 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> By the distributive law:\r<BR>\n" );
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document.write( "square root of 7 * (square root of 5 - square root of 3) = \r<BR>\n" );
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document.write( "(square root of 7 * square root of 5) - (square root of 7 * square root of 3)\r<BR>\n" );
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document.write( "Using the rule that the product of square roots is the square root of the product or in other words:\r<BR>\n" );
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document.write( "square root of (x*y) = square root x * square root y we have:\r<BR>\n" );
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document.write( "square root of 7 * square root of 5 = square root of (7*5) = square root of 35 \r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "square root of 7 * square root of 3 = square root of (7*3) = square root of 21\r<BR>\n" );
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document.write( "Since neither 35 nor 21 have any perfect square factors to simplify we have:\r<BR>\n" );
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document.write( "(square root of 35 - square root of 21) as the final answer.   </SPAN>\n" );
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