document.write( "Question 245000: find the inverse of log(base 2) (x^5)\r
\n" ); document.write( "\n" ); document.write( "when i worked it out i got 2^x^5....but i didnt know if that could be simplified any further?
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Algebra.Com's Answer #179110 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \"y=log%282%2C%28x%5E5%29%29\". Now swap x and y to get \"x=log%282%2C%28y%5E5%29%29\". The goal here is to solve for y.\r
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\n" ); document.write( "\n" ); document.write( "\"x=log%282%2C%28y%5E5%29%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2%5Ex=y%5E5\" Convert to exponential form.\r
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\n" ); document.write( "\n" ); document.write( "\"root%285%2C2%5Ex%29=y\" Take the 5th root of both sides to isolate 'y'\r
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\n" ); document.write( "\n" ); document.write( "So the inverse is \"root%285%2C2%5Ex%29\"
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