document.write( "Question 244987: x=12^(log base 12 of 5)\r
\n" ); document.write( "\n" ); document.write( "I think that's the same as:\r
\n" ); document.write( "\n" ); document.write( "x=12^(5 log base 12), but I'm just trying to follow previous patterns and I'm lost \n" ); document.write( "

Algebra.Com's Answer #179109 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
It turns out that $\"a%5Elog%28a%2C%28b%29%29=log%28a%2C%28a%5Eb%29%29=b\"$ . In this problem, it's useful to know $\"a%5Elog%28a%2C%28b%29%29=b\"$ . \r
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\n" ); document.write( "\n" ); document.write( "In this case, a=12 and b=5. So $\"x=12%5E%28log%2812%2C%285%29%29%29=5\"$ which means that the answer is $\"x=5\"$ \n" ); document.write( "

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