document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244987>Question 244987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x=12^(log base 12 of 5)\r<BR>\n" );
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document.write( "I think that's the same as:\r<BR>\n" );
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document.write( "x=12^(5 log base 12), but I'm just trying to follow previous patterns and I'm lost </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179108 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You are thinking of the rule that log base 12 of 5^n = n * (log base 12 of 5) which doesn't apply here.\r<BR>\n" );
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document.write( "The base 12 log of a number, say z, is the power that 12 needs to be raised to to produce the number z: \r<BR>\n" );
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document.write( "z = log base 12 of 5 if and only if 12^z = 5 by definition of a log.\r<BR>\n" );
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document.write( "In this case x = log base 12 of 5 is the number that 12 would need to be raised to to produce the number 5. So actually raising 12 to the (log base 12 of 5) produces a value of 5. \r<BR>\n" );
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