document.write( "Question 244989: One antifreeze solution is 10% alcohol. Another antifreeze solution is 18% alcohol. How many liters of each antifreeze solution should be combined to create 20 liters of antifreeze solution that is 15% alcohol? \n" ); document.write( "
Algebra.Com's Answer #179106 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x = liters of first solution. \n" ); document.write( "y = liters of second solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula for amount of alcohol required in the new solution is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + .18 *y = .15 * 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "formula for total amount of solution required is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 2 equations that have to be solved simultaneously.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since x + y = 20, this means that y = 20-x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute in the other equation and solve for x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + .18 *y = .15 * 20 becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + .18 * (20-x) = .15 * 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + .18 * 20 - .18 * x = .15 * 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify further to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + 3.6 - .18 * x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-.08 * x + 3.6 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 3.6 from both sides of the equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-.08 * x = -.6\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by -.08 to get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = -.6 / -.08 = 7.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if x = 7.5, then y = 20-7.5 = 12.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we have x = 7.5 litres and y = 12.5 liters\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute in original solution equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * x + .18 *y = .15 * 20 becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".10 * 7.5 + .18 * 12.5 = .15 * 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".75 + 2.25 = 3 which is true so the answer is confirmed to be good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".1 * 7.5 liters of solution 1 + .18 * 12.5 liters of solution 2 = .15 * 20 liters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you need 7.5 liters of solution 1 and 12.5 liters of solution 2 to make a total of 20 liters.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The percent alcohol will be .1 * 7.5 + .18 * 12.5 = 3 liters of alcohol.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 liters / 20 liters = 15% of the new solution.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |