document.write( "Question 244928: john needs to rent a theatre for a concert. The theatre charge $700 plus $3per person. john plans to selltickets for $10 per person. let C represent the cost of the eventand N the number of people attending the concert.
\n" ); document.write( "Write a linear system to represent the situation.
\n" ); document.write( "How many tickets must be sold to break evan?
\n" ); document.write( "what will be the total cost be?
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Algebra.Com's Answer #179101 by Theo(13342)\"\" \"About 
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c = 700 + 3 * n\r
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\n" ); document.write( "\n" ); document.write( "c = cost
\n" ); document.write( "n = number of persons attending.\r
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\n" ); document.write( "\n" ); document.write( "r = 10 * n\r
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\n" ); document.write( "\n" ); document.write( "r = revenue
\n" ); document.write( "n = number of persons attending.\r
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\n" ); document.write( "\n" ); document.write( "he will break even when r = c\r
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\n" ); document.write( "\n" ); document.write( "this makes:\r
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\n" ); document.write( "\n" ); document.write( "10 * n = 700 + 3 * n\r
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\n" ); document.write( "\n" ); document.write( "subtract 3 * n from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "7 * n = 700\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of this equation by 7 to get:\r
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\n" ); document.write( "\n" ); document.write( "n = 100\r
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\n" ); document.write( "\n" ); document.write( "he should break even when 100 peopled attend.\r
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\n" ); document.write( "\n" ); document.write( "cost for 100 people = 700 + 300 = 1000\r
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\n" ); document.write( "\n" ); document.write( "revenue for 100 people = 10 * 100 = 1000\r
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\n" ); document.write( "\n" ); document.write( "that's the break even point.\r
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