document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4056>Question 4056</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Upstream, downstream. Junior’s boat will go 15 miles per hour in still water. If he can go 12 miles downstream in the same amount of time as it takes to go 9 miles upstream, then what is the speed of the current? D R T Downstream 12 x 12/x Upstream 9 x 9/x The speed of current is 1/5 mph. On the right track or totally off? So far..... 12/x - 9/x = 15 ; 3/x = 15 ; 3 = 15x ; 3/15 = x ; 1/5 = x ; Am I on the right track?...Thank you <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1791 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Let the speed of the current be x mph.<BR>\n" );
document.write( " [Note x should be less  than 15 mph, for otherwise theboat cannot move<BR>\n" );
document.write( " when gotupstream.]\r<BR>\n" );
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document.write( " Downstream speed = x + 15. (sum of the speeds)<BR>\n" );
document.write( " Upstream speed = 15-x, (difference of the speeds)\r<BR>\n" );
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document.write( " Now we have 12/(x+15) = 9/(15-x) or<BR>\n" );
document.write( " 4(15-x) = 3(x+15)<BR>\n" );
document.write( " so 7x = 15 , x = 15/7 mph.\r<BR>\n" );
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document.write( " You did completely wrong , try to think about it.\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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