document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=244931>Question 244931</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the value of x if you have an isoceles triangle with one angle having a value of x+3 degrees and the base angles having a value of 2x - 2 degrees?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #179096 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=179096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> sum of the angles of a triangle is 180 degrees.\r<BR>\n" );
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document.write( "one angle is x+3 degrees.\r<BR>\n" );
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document.write( "2 angles are 2x-2 degrees each.\r<BR>\n" );
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document.write( "sum of the angles of the triangle equals\r<BR>\n" );
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document.write( "x + 3 + 2 * (2x - 2) equals:\r<BR>\n" );
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document.write( "x + 3 + 4x - 4 equals:\r<BR>\n" );
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document.write( "5x - 1\r<BR>\n" );
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document.write( "this sum equals 180 degrees so:\r<BR>\n" );
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document.write( "5x - 1 = 180\r<BR>\n" );
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document.write( "add 1 to both sides to get 5x = 181\r<BR>\n" );
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document.write( "divide both sides by 5 to get x = 181/5 = 36.2 degrees\r<BR>\n" );
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document.write( "substitute in original equation to see if this is true.\r<BR>\n" );
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document.write( "x + 3 + 2 * (2x - 2) = 180 becomes:\r<BR>\n" );
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document.write( "36.2 + 3 + 2*(72.4-2) = 180 becomes:\r<BR>\n" );
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document.write( "36.2 + 3 + 2*70.4 = 180\r<BR>\n" );
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document.write( "simplify to get:\r<BR>\n" );
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document.write( "36.2 + 3 + 140.8 = 180\r<BR>\n" );
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document.write( "simplify further to getg:\r<BR>\n" );
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document.write( "180 = 180 which is true confirming that x = 36.2 is a good answer.\r<BR>\n" );
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